Experimental process:
Imitation NBA rubber ball: This kind of ball is of average quality, but the price is relatively cheap. It is bought by some people who don't know much about basketball and looks brighter than the original one.
Chinese and Korean mixed race, actor, representative work of Korean drama On Air
//Technical interview
谁知，内侍去了肃王府回来说，肃王病了，正卧床不起呢。
When ex-police officer Tom hears news of the abduction of Julie Delaney, he leaves his partner Sam and their beautiful coastal home and heads straight to the crime scene.
ROCKY白手创业，四位与他同生死共患难的朋友—行远、国楷、浩哲、佳怡（唐振刚、杨佑宁、朴熙植、刘诗诗 饰） 成了他的事业伙伴，他们各有所长，在不同的领域帮着ROCKY共创事业的高峰，一路辛苦的创业，ROCKY养成了给MAY打电话的习惯，尽管从来没有接通过……佳怡在ROCKY身边，一直支持着ROCKY，她期待着哪天，随着时间的过去，MAY会彻底消失，她会赢得ROCKY的心。 佳怡尽心尽力为ROCKY达成「上海五万人」的目标，却不知道这一切是为了另一个女人……
今晨突然接到消息，重病的伯父撒手人寰，三问没想到会如此突然。
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5. Check the calculation, select another front row of defense data, and continue to learn from each other to verify the correctness of the formula.
周家顿时热闹起来。
方略证券公司是在金融界名声卓著的地方性证券机构，总经理唐进洲是一位雄心勃勃的投资家，为人正直，精于业务。但是他犯了一个致命的错误，在自己不知情中，妻子苏可，接收了梁文仪书记的儿子梁宽注册的公司。该公司的资金是梁宽擅自截留的国有资产。
Move
一个韩裔加拿大家庭经营便利店的不幸遭遇。
有主见、成绩又好的女大学生洪雪不知道为什么老是觉得同系的人气学长刘正是一个不能信任的人，但是正因为刘正的好心相助，洪雪才得以继续坚持自己的学业。虽然觉得刘正有些奇怪，但两人最终稀里糊涂地交往了。尽管如此，交往后的刘正还是不会轻易吐露自己的内心。
"They communicate with other bank colleagues and telecom providers, and directly cooperate with service providers. Of course, they have no choice, because they cannot survive in a harsh and safe world on their own," Price pointed out.
两年来勤奋的气功修为，差不多已经把那股子暴戾之气完全融入经脉之中，功力增长不少，何况手上还有锋利无比的断水剑，有与嚣张轻敌的平武一战的实力。
为韩国版【麻辣鲜师】，描写校园内的青春纪事。主角人物李世灿外表很帅，颇受女孩 子欢迎。但因为个性冷酷 ... 一集东光高校新学期开始，二年五班所有的学生全部聚集在一起，其中游多颖是从乡下学校转学过来的学生，活泼开朗的她开学第二天就被朴光道老师受到处罚，原因是穿著布鞋来学校，多颖认为这种校规不合理，并要求朴老师进一步说明原因，这句话害自己跪了一个上午。在一堂话 法课上，她发挥了犀利的口才……
We can understand that the responsibility chain mode is a chain composed of processing requests. Requests are passed between these objects in turn until we encounter an object that can process it. We call these objects nodes in the chain. For example, object a sends a request to object b. If object b does not process, it will give the request to c. If object c does not process, it will give the request to d, and so on, until one object can process the request. Of course, if no object processes the request, then the request will leave the chain.
