1986年，汉城亚运会期间，韩国举国上下沉浸在体育竞技的热闹氛围之中。但在位于韩国西南部的极乐岛上，却发生了惨绝人寰且扑朔迷离的连环杀人案。极乐岛位于大海中央，岛上只有17为居民，人们安居乐业，质朴风趣，尽职尽责的于成友大夫关爱大家的健康，是岛民们最为依赖的外来者。适逢70岁高龄的金哲英爷爷寿辰，岛民们聚在一起饮食歌舞，畅玩通宵。可就在次日清晨，两名电工遭人残忍杀害，岛上一时间人心惶惶。人们议论纷纷，相互猜忌。在此之后，残忍的凶手并未收手，而是展开新一轮的屠杀。 名为极乐的小岛，变成最为恐怖和血腥的人间地狱……
Repeated decoction can be used to obtain dye solution for 4-6 times
……夏林离开了，陈启也走出茶馆。
No.33 Yang Zishan
一个突然到来的访客，把平凡的古董店店主许愿（夏雨饰）带进了一个做梦都想不到的阴谋中，一件坊间传说的稀世珍宝，竟然和自己有着千丝万缕的联系，一个几十年前做的局，竟然已经编排进自己的命运。许愿将使出浑身解数，置身生死之间，和蛰伏了几十年的各方神圣斗智斗勇，和古董江湖里造假做局的各种奇技淫巧一一遭遇。
见到英布的时候，尹旭立即出声赞扬慰勉。
《我爱李泰利 아이러브 이태리》讲述了十四岁的金恩东（白承焕 饰）和年长他六岁的和顺心（金恩英 饰）有着一纸婚约，然而顺心对这门家长指定的婚事十分不满，她喜欢的是成熟而又稳重的集团常务崔胜宰（杨振宇 饰），这令喜欢着顺心的金恩东心里很不是滋味。
至此大江之南的土地已经全部为越国所掌控，越国也真正升级为一个足矣和楚汉两国对抗的国家，实力不容小觑。
An NBA game lasts 48 minutes and consists of four sections, each of which lasts 12 minutes.
谢谢你们。
进入院内，青石板铺就的通道，呈十字型。
29. For each identified problem, if one department proposes that the problem that needs to be solved in coordination requires the cooperation of another department, then after the problem is discussed and determined at the meeting, it is stated that it should be included in the plan of the coordination department for the current week or month, and the department must give special feedback on the implementation of the problem at the next regular meeting. If it is completed before the next regular meeting, it is suggested to give feedback at any time. The department manager will give feedback to the deputy chief in charge, and then the deputy chief in charge will give feedback to higher-level leaders or assessment departments. Of course, to consider the size and importance of the problem, general minor problems can only be fed back to the competent deputy general office or the competent assessment department.
该剧主要讲述一对准夫妻孟云、艾达，在领结婚证过程中意外频发。两人的诸多前任不断出现，几次三番阻挠他们的婚姻大事，使得他们对彼此的感情有了困惑和不安。同时在一次次突发情况中，两人更加互相了解，携手继续他们的“领证历险记”。
香荽又叹了口气道：知道我家为啥被抄家吗？她睁着黑漆漆的眼睛望着二人道：因为神龟。
Updated February 7
《mabuve》是游戏品牌：Age策划制作的2003年发售的冒险游戏。
The above is just a synchronous chain of responsibilities, We let each node function return a specific value "nextSuccessor" synchronously, To indicate whether to pass the request to the next node, we will often encounter AJAX asynchronous requests in our development. After the request is successful, we need to do something so-and-so. At this time, if we apply the above synchronous request again, it will not take effect. Let's understand and use asynchronous responsibility chain to solve this problem. We add another prototype method Chain.prototype.next to the Chain class to manually pass the request to the next node in the responsibility chain.
